Dielectric constant of pure water is 81. Its permittivity will be

7.12 \times 10^{- 10} M K S u n i t s

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8.86 \times 10^{- 12} M K S u n i t s

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1.02 \times 10^{13} M K S u n i t s

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Cannot be calculated

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Solution

The correct option is A $7.12 \times 10^{- 10} M K S u n i t s$
$ε_{0} = K ε_{0} = 81 \times 8.854 \times 10^{- 12} = 7.17 \times 10^{- 10} M K S u n i t s$

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Dielectric constant of pure water is 81. Its permittivity will be

The correct option is A 7.12×10−10MKS unitsε0=Kε0=81×8.854×10−12=7.17×10−10MKS units

The correct option is A $7.12 \times 10^{- 10} M K S u n i t s$
$ε_{0} = K ε_{0} = 81 \times 8.854 \times 10^{- 12} = 7.17 \times 10^{- 10} M K S u n i t s$