Question

Diethyl ether $C_4{H}_{10}O$, used medically as an anesthetic, is prepared from ethyl alcohol $C_2{H}_{5}OH$ in presence of an acid.

$2C_2{H}_{5}OH\underset{{140}^0}{\overset{acid}{\to }}{C}_2{H}_{5}O{C}_2{H}_5+H_{2}O$

Calculate the $\%$ yield if $46g$ of ethyl alcohol gives $30g$ of ether.

Answer 1

Gives reach is : $2C_2{H}_{5}OH\underset{{140}^{0}C}{\overset{acid}{\to }}{C}_2{H}_{5}O{C}_2+H_{2}O$

$2\times 46=92g$ $74g$

$\Rightarrow 92g7ethanol\iff 74g$ of ether

$\Rightarrow 46g7ethnol\iff \frac{74}{92}\times 46=37g$ of ether

attained yield $=30g$

$\%$ yield $=\frac{30}{37}\times 100\%=81.081\%$