Diethyl ether can be decomposed with:

H I

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K M n O_{4}

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N a O H

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H_{2} O

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Solution

The correct option is B $H I$
On heating with concentrated Hydrogen iodide $(H I)$ the C-O bond in ethers breaks forming alcohol and alkyl iodide. For example,

$C_{2} H_{5} - O - C_{2} H_{5} + H I ⟶ C_{2} H_{5} - I + C_{2} H_{5} O H$

On boiling with excess of concentrated Hydrogen iodide $(H I)$ , Alkyl iodide is formed.

$C_{2} H_{5} - O - C_{2} H_{5} + 2 H I ⟶ 2 C_{2} H_{5} - I + H_{2} O$

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H I

H_{2} O

H I

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