Question

Difference between $\Delta H$ and $\Delta E$ for the combusion of liquid methane at ${27}^{0}C$ is:

• A. $47.48J$
• B. $2493J$
• C. $1486J$
• D. $5.73J$

Answer 1

The correct option is B $2493J$

$C{H}_4\left(l\right)+2O_2\left(g\right)\to C{O}_2\left(g\right)+2H_{2}O\left(l\right)$

For a chemical reaction involving gaseous species ,

$△H=△E+△n_{g}RT$

$△H-△E=-1\times 8.31\times 300J=-2493J$