Question

Difference between $n^{th}$ and $(n+1{)}^{th}$ Bohr’s radius of ‘H’ atom is equal to it’ s $(n–1{)}^{th}$ Bohr’s radius. The value of $n$ is :

• A. 1
• B. 2
• C. 3
• D. 4

Answer 1

The correct option is D 4

The Bohr's radius of Hydrogen atom is given by
$r=0.529n^2$
$0.529\left[\right(n+1{)}^2-n^2]=0.529(n-1{)}^2$
$\Rightarrow 2n+1=n^2+1-2n$
$\Rightarrow n=0,4$