Difference between $n t h$ and $(n + 1) t h$ Bohr's radius of hydrogen atom is equal to $(n - 1) t h$ Bohr's radius. The value of $n$ is

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Solution

The correct option is D $4$
Given,
${(n + 1)}^{2} - n^{2} = {(n - 1)}^{2} \Rightarrow 1 + 2 n = n^{2} + 1 - 2 n \Rightarrow n^{2} = 4 n \Rightarrow n = 4$

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Difference between $n^{t h}$ and $(n + 1)^{t h}$ Bohr's radius of `H' atom is equal to it's $(n - 1)^{t h}$ Bohr's radius. The value of n is approximately ___.

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Difference between nth and (n+1)th Bohr's radius of hydrogen atom is equal to (n−1)th Bohr's radius. The value of n is

The correct option is D 4Given,(n+1)2−n2=(n−1)2⇒1+2n=n2+1−2n⇒n2=4n⇒n=4

Difference between $n t h$ and $(n + 1) t h$ Bohr's radius of hydrogen atom is equal to $(n - 1) t h$ Bohr's radius. The value of $n$ is

The correct option is D $4$
Given,
${(n + 1)}^{2} - n^{2} = {(n - 1)}^{2} \Rightarrow 1 + 2 n = n^{2} + 1 - 2 n \Rightarrow n^{2} = 4 n \Rightarrow n = 4$