Question

Difference in temperature of a thermocouple is ${250}^{0}C$, if $a=15\mu V{/}^{0}C$ and $1.875$ $mV$ e.m.f. is generated, then the value of $b$ is

• A. $-0.03\mu V{/}^0{C}^2$
• B. $-0.03\mu V{/}^{0}C$
• C. $-0.06\mu V{/}^0{C}^2$
• D. $-0.06\mu V{/}^{0}C$

Answer 1

Answer: (A)

$-0.03\mu V{/}^0{C}^2$

For peltier effect,
thermo EMF
$E=at+b{t}^2$
$\therefore 1.875\times {10}^3=15\left(250\right)+b(250{)}^2$
$\therefore b=-0.30\mu V{/}^0{C}^2$