Difference in the number of protons of the largest element of the fourth period and the smallest element of the third period is:

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Solution

The correct option is B 2
The largest element of the fourth period is $K (Z = 19)$ .

The smallest element of the third period is $C l (Z = 17)$ .

Therefore, the difference in the number of protons is $19 - 17 = 2$ $.

So, the correct option is $B$

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