Difference in the oxidation number of chromium in $C r_{2} O_{3}$ and $K_{2} C r_{2} O_{7}$ :

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Solution

The correct option is B 3
Let the oxidation number of $C r$ in $K_{2} C r_{2} O_{7}$ is x. Hence, $2 \times 1 + 2 \times x + (- 2) \times 7 = 0$ .
So x = +6
Similarly for $C r_{2} O_{3}$ ,
$2 \times x + 3 \times (- 2) = O$
So x = +3
Hence, the difference is 3.

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Similar questions

C r_{2} O_{3}

K_{2} C r_{2} O_{7}

K_{2} C r_{2} O_{7} + S O_{2} H^{+} - - \to

N

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K_{2} C r_{2} O_{7}

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