Question

Difference of $\sigma$ and $\pi$ bonds in $C(CN{)}_4$ is:

Answer 1

In $CN$, there is one $\sigma$ bond and two $\pi$ bond and $CN$ bonded to $C$ with $\sigma$ bond, In ${\left(CN\right)}_4$ there will be 8 $\pi$ bonds and 4 $\sigma$ bonds
$\therefore$ total number of $\sigma$ bonds in $C{\left(CN\right)}_4=$8 and
total number of $\pi$ bonds in $C{\left(CN\right)}_4=$8
So difference is 0