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Question

Different words being formed by arranging the letters of the word "INTERMEDIATE". All the words obtained are written in the form of a dictionary,
Number of permutations if the words start with E & ends with I

A
907200
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B
10!2!
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C
3628800
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D
None of these
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Solution

The correct option is B 907200
We fix E and I at the beginning and the end respectively.

E I
The remaining letters are:
NTERMDAT
Thus, total number of permutations = 10!2!2!=907200 (we have 10 letters in between I and E...and in which 2E,2T are...there)
Hence, (a) is correct.

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