Question

Differential the following functions w.r.t. $x$:
$\frac{2x+3}{x^2-5}$

Answer 1

$\frac{dy}{dx}=\frac{(x^2-5)\left(2\right)-(2x+3)\left(2x\right)}{(x^2-5{)}^2}$

$\frac{dy}{dx}=\frac{2x^2-10-4x^2-6x}{(x^2-5{)}^2}$

$\frac{dy}{dx}=\frac{-2x^2-6x-10}{(x^2-5{)}^2}=\frac{-2(x^2+3x+5)}{(x^2-5{)}^2}$