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Question

Differentiate: $$2\sqrt{x^2+b^2}$$


Solution

Let $$y=2\sqrt { { x }^{ 2 }+{ b }^{ 2 } } $$
$$\Rightarrow \cfrac { dy }{ dx } =\cfrac { 1 }{ 2\sqrt { { x }^{ 2 }+{ b }^{ 2 } }  } 2x\\ \Rightarrow \cfrac { dy }{ dx } =\cfrac { x }{ \sqrt { { x }^{ 2 }+{ b }^{ 2 } }  } $$

Mathematics

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