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Molarity

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Question

Differentiate between molarity and molality for a solution. How does a change in temperature influence their values?

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Solution

$1.$ Molarity is moles of solute dissolved per litre solution.
$M = \frac{M o l e s o f s o l u t e}{V (l i t r e s)}$
Since, $V \propto T, M \propto \frac{1}{T}$ (As evident from osmotic pressure equation $π = i C R T$ is molarity)
$2.$ Molality is mass of solute per kg solvent.
$m = \frac{M o l e s o f s o l u t e}{M a s s o f s o l v e n t (k g)}$
It does not depend upon temperature.

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