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Question

Differentiate sec1x

A
1|x|(x21)
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B
1|x|(x2+1)
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C
1x(x21)
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D
1x(x21)
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Solution

The correct option is A 1|x|(x21)
Let, y=sec1xsecy=x
Differentiating both side w.r.t x
secy.tanydydx=1
dydx=1secy(sec2y1)=1|x|(x21)

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