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Question

Differentiate from the first principles:
(i) 2x (ii) (x1)2

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Solution

(i)2x
f(x)=h02(x+h)f(x)h
=limh02(x+h)2xh
=limh02x+2h2xh
=limh02hh
limh02
=2

(ii) (x1)2
f(x)=x0+x+h)f(x)h
=limh0+(x+h1)2(x1)2h
=limh0+x+h1+x1)(x+h1x+1)h
=limh0+(2x2+h)(h)h
=2(x1)

1077459_1170911_ans_bfd548c2cea24c74a8ea64e40894f978.png

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