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Question

Differentiate In tanx with respect to sin1(ex)

A
ex1e2xsinxcosx
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B
ex1e2xsinxcotx
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C
ex1+exsinxcosx
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D
ex1+e2xsinxsecx
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Solution

The correct option is B ex1e2xsinxcosx
d(lntanx)dsin1ex=d(ln(tanx))dx÷dsin1exdx
=1.sec2xtanxex1e2x
=1sinxcosxex1e2x [A]

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