wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Differentiate (logx)cosx w.r.t x.

Open in App
Solution

y=(logx)cosx
logy=log[(logx)]cosx
logy=cosxlog(logx)
Differentiating w.r.t x
1ydydx=cosx1logx1xlog(logx)sinx
dydx=y[cosxxlogxsinlog(logx)]
dydx=(logx)cosx[cosxxlogxsinlog(logx)]

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Logarithmic Differentiation
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon