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Question

Differentiate (logx)cosx w.r.t x.

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Solution

y=(logx)cosx
logy=log[(logx)]cosx
logy=cosxlog(logx)
Differentiating w.r.t x
1ydydx=cosx1logx1xlog(logx)sinx
dydx=y[cosxxlogxsinlog(logx)]
dydx=(logx)cosx[cosxxlogxsinlog(logx)]

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