CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Logarithmic Differentiation

Differentiate...

Question

Differentiate
$log (x^{x} - 2^{sin x})$

Open in App

Solution

$y = l o g (x^{x} - 2^{s i n x})$
$e^{y} = x^{x} - 2^{s i n x}$
Diffferentiating both sides wrt x
$e^{y} \frac{d y}{d x} = x^{x} (1 + l o g x) - 2^{s i n x} c o s x . l o g 2$
$\frac{d y}{d x} = \frac{x^{x} (1 + l o g x) - 2^{s i n x} c o s x . l o g 2}{x^{x} - 2^{s i n x}}$

Suggest Corrections

thumbs-up

0

Similar questions

Q. Differentiate w.r.t

x

(log x)^{x}

Q. Differentiate (log x)^x with respect to log x

Q. Differentiate the following function:

x^{log x} + {(log x)}^{x}

Q. Differentiate

(log x)^{x} + x^{log x}

with respect to

x

Q. Differentiate the function w.r.t.

x

.

(log x)^{x} + x^{log x}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Logarithmic Differentiation

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Logarithmic Differentiation

Standard XII Mathematics

Join BYJU'S Learning Program

CrossIcon