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Question

Differentiate log1+cos2x(1e2x) w.r.t. x.

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Solution

Derivative of log1+cos2x(1e2x) can be easily evaluated using chain rule

Derivative of log1+cos2x(1e2x) =(1e2x1+cos2x)× Derivative of 1+cos2x1e2x wrt x
(1e2x1+cos2x)× (1e2x)(Sin2x)(1+cos2x)(2e2x)(1e2x)2
(1e2x)(Sin2x)(1+cos2x)(2e2x)(1e2x)(1+cos2x)

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