Question

Differentiate:

$\log (x\tan x+\sec x)$

Answer 1

$\frac{dy}{dx}=\frac{1}{x\tan x+\sec x}\frac{d(x\tan x+\sec x)}{dx}$

$\frac{dy}{dx}=\frac{\tan x+x{\sec }^{2}x+\sec x\tan x}{x\tan x+\sec x}$

$\frac{dy}{dx}=\frac{\tan x+\sec x(x\sec x+\tan x)}{x\tan x+\sec x}$