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Question

Differentiate
( sin1x)logx

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Solution

Let y=(sin1x)log(x)
Differentiate on both sides w.r.t x
dydx=ddx(sin1(x))logx+sin1x(ddx(logx))
=logx1x2+sin1(x)x
dydx=logx1x2+sin1(x)x

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