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Byju's Answer
Standard XII
Mathematics
Product Rule of Differentiation
Differentiate...
Question
Differentiate the following equation:
e
x
l
o
g
√
x
t
a
n
x
Open in App
Solution
d
d
x
(
e
x
l
o
g
√
x
t
a
n
x
)
Apply product rule,
=
l
o
g
√
x
×
t
a
n
x
d
d
x
(
e
x
)
+
e
x
×
t
a
n
x
d
d
x
(
l
o
g
√
x
)
+
e
x
l
o
g
√
x
d
d
x
(
t
a
n
x
)
=
l
o
g
√
x
×
t
a
n
e
x
+
e
x
t
a
n
x
1
2
x
+
e
x
l
o
g
√
x
×
s
e
c
2
x
=
1
2
l
o
g
x
×
t
a
n
x
×
e
x
+
1
t
a
n
x
2
x
e
x
1
2
l
o
g
x
s
e
c
2
x
[
∵
l
o
g
√
x
=
1
2
l
o
g
x
]
=
1
2
e
x
(
l
o
g
x
×
t
a
n
x
+
t
a
n
x
x
+
l
o
g
x
s
e
c
2
x
)
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