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Question

Differentiate the following equation:
x3 ex cos x

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Solution

We have,
ddx(x3 ex cos x)
=ex cos x ddx(x3)+x3 cosx ddx(ex)+x3ex ddx(cos x) [Using product rule]
=ex cosx×3x2+x3 cosx×ex+x3ex(sin x)
=x2 ex(3 cosx+x cosx+x(sinx))
=x2 ex(3cos x+x cos xx sin x)


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