Question

Differentiate the following function with respect to $x$
$\cos h^{-1}(4+3x)$

Answer 1

$\frac{d}{dx}\left(cos{h}^{-1}x\right)=\frac{1}{\sqrt{x^2-1}}$

$\frac{d}{dx}\left(cos{h}^{-1}\right(4+3x\left)\right)=\frac{1}{\sqrt{(3+4x{)}^2-1}}\times \frac{d}{dx}(4+3x)$

$\Rightarrow \frac{d}{dx}\left(cos{h}^{-1}\right(4+3x\left)\right)=\frac{3}{\sqrt{(4+3x{)}^2-1}}$