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Question

Differentiate the following functions from first principles:

sin−1 (2x + 3)

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Solution

Let fx=sin-12x+3 fx+h=sin-12x+h+3 fx+h=sin-12x+2h+3 ddxfx=limh0fx+h-fxh =limh0sin-12x+2h+3-sin-12x+3h =limh0sin-12x+2h+31-2x+32-2x+31-2x+2h+32h sin-1x-sin-1y=sin-1x1-y2-y1-x2 =limh0sin-1zz×zhwhere, z=2x+2h+31-2x+32-2x+31-2x+2h+32 and limh0sin-1hh=1 =limh0zh =limh0 2x+2h+31-2x+32-2x+31-2x+2h+32 h =limh02x+2h+321-2x+32-2x+321-2x+2h+32h2x+2h+31-2x+32+2x+31-2x+2h+32 Rationalizing numerator =limh02x+32+4h2+4h2x+31-2x+32-2x+321-2x+32-4h2-4h2x+3h2x+2h+31-2x+32+2x+31-2x+2h+32 =limh02x+32+4h2+4h2x+3-2x+34-4h22x+32-4h2x+33-2x+32+2x+34+4h22x+32+4h2x+33h2x+2h+31-2x+32+2x+31-2x+2h+32 =limh04hh+2x+3h2x+2h+31-2x+32+2x+31-2x+2h+32 =42x+32x+31-2x+32+2x+31-2x+32 =42x+322x+31-2x+32 =21-2x+32 ddxsin-12x+3=21-2x+32

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