Differentiate the following functions w.r.t.x :
$3^{x} + x^{3} + 3^{3}$

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Solution

Let $y = 3^{x} + x^{3} + 3^{3}$
Differentiating w.r.t $x$
$\frac{d y}{d x} = 3^{x} log 3 + 3 x^{3 - 1} + 0 = 3^{x} log 3 + 3 x^{2}$

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