Differentiate the following functions with respect to x :
(2x2+1)(3x+2)
We have,
ddx(2x2+1)(3x+2)
=(3x+2)ddx(2x2+1)+(2x2+1)ddx(3x+2)
[Using product rule]
=(3x+2)(4x+0)+(2x2+1)(3+0).
=(12x2+8x+6x2+3)
=18x2+8x+3
2x2+3x+4x
x2+1x+1