Differentiate the following functions with respect to $x$
(a) $cos h^{3} 2 x$
(b) $tan h (sin x)$

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Solution

$(a) \frac{d}{d x} c o s h^{3} 2 x = 3 c o s h^{2} 2 x \times s i n h 2 x \times 2$

= $6 c o s h^{2} 2 x \times s i n h 2 x$

$(b) \frac{d}{d x} t a n h (s i n x) = s e c h^{2} (s i n x) \times c o s x$

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