Differentiate the following functions with respect to x
cos(x3) sin2 (x5)
Let y = cos3 sin2 (x5)
Differentiate both sides w.r.t. x,
dydx=ddx{cos x3 sin2(x5)}=cos x3 ddxsin2(x5)+sin2(x5)ddx(cos x3)
[Using product rule ddx(uv)=uddxv+uddxv]
= (cos x3)(2sin x5)ddx(sin x5)+sin2(x5)(−sin x3)ddx(x3)
[using chain rule ddxf(g(x))=f′(x)ddxg(x)]
=(cos x3)(2sin x5)(cos x5)ddx(x5)+sin2(x5)(−sin x3)(3x2)
(Using chain rule)
= (cos x3)(2sin x5)(cos x5)(5x4)−sin2(x5)(sin x3)(3x2)