Differentiate the following functions with respect to x :
1+log x1−log x
We have,
ddx(1+log x1−log x)
using quotient rule,
(1−log x)ddx(1+log x)−(1+log x)ddx(10log x)(1−log x)2
=(1−log x)×1x−(1+log x)(−1x)(1−log x)2=1−log x+1+log xx(1−log x)2=2x(1−log x)2