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Question

Differentiate the following functions with respect to x :

4x+5 sin x3x+7 cos x

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Solution

Let y=4x+5 sin x3x+7 cos x

Differentiating y w.r.t. x, we get

dydx=(3x+7 cos x)ddx(4x+5 sin x)(4x+5 sin x)ddx(3x+7 cos x)(3x+7 cos x)2 (By quotient formula)

=(3x+7 cos x)(4×1+5 cos x)(4x+5 sin x)(37 sin x)(3x+7 cos x)2

=12x+15x cos x+28 cos x+35 cos2x12x+28 x sin x15 sin x+35 sin2x(3x+7 cos x)2

=35(cos2x+sin2x)+15 x cos x+28 cos x+28 x sin x15 sin x(3x+7 cos x)2

=35+15 x cos x+28 cos x+28 x sin x15 sin x(3x+7 cos x)2 [ sin2x+cos2=1]


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