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Question

Differentiate the following functions with respect to x :

sin xx cos xx sin x+cos x

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Solution

We have,

ddx(sin xx cos xx sin x+cos x)

Apply quotient rule, we get

=(x sin x+cos x)ddx(sin xx cos x)(sin xx cos x)ddx(x sin x+cos x)(x sin x+cos x)2

=(x sin x+cos x){cos x(dxdxcos x+cos xdxdx)}(sin xx cos x)(dxdxsin x+sin xdxdx)+ddxcos x(x sin x+cos x)2

=(x sin x+cos x)(cos x+x sin xcos x)(sin xx cos x)(x cos x+sin xsin x)(x sin x+cos x)2

=(x sin x+cos x)x sin x(sin xx cos x)×cos x(x sin x+cos x)2=x2sin2x+x sin x cos xx sin x cos x+x2cos2x(x sin x+cos x)2

=x2(sin2x+cos2x)(x sin x+cos x)2 ( sin2x+cos2=1) =x2x sin x+cos x

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