Differentiate the following functions with respect to x :
(x3+1)(x−2)x2
We have,
ddx{(x3+1)(x−2)}x2
=ddx{x4−2x3+x−2}x2
=ddx(x2−2x+x−1−2x−2)
=ddx(x2)−2dxdx+dx−1dx−2dx−2dx
=2x−2−1x2+2.2x3
=2x−2−1x2+4x3
x33−2√x+5x2
x2−x+1x2+x+1
3x+x3+33
x2+1x+1