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Question

Differentiate the following functions with respect to x :

x tan xsec x+tan x

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Solution

We have,

ddx(x tan xsec x+tan x)

Using quotient rule, we get

=(sec x+tan x)ddx(x tan x)(x tan x)ddx(sec x+tan x)(sec x+tan x)2 =(sec x+tan x)(x sec2x+tan x)(x tan x)(sec xtan x+sec2x)(sec x+tan x)2 [Using product rule]

=(sec x+tan x)(x sec2x+tan x)x sec x+tan2xx tan x sec2x(sec x+tan x)2

=(sec x+tan x)(x sec2x+tan x)x tan x(sec x tan x+sec2x)(sec x+tan x)2

=(sec x+tan x)(x sec2x+tan x)x tan xsec x(sec x+tan x)(sec x+tan x)2

=(sec2x+tan xx tan xsec x)(sec x+tan x)(sec x+tan x)2

=(xsec2+tan xxtan xsec x)sec x+tan x=x sec(sec xtan x)+tan x(sec x+tan x)


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