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Question

Differentiate the following functions with respect to x
(logx)logx

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Solution

Let y=(logx)logx

y=e(logx)log(logx) [ y=axcan be written as y=exloga]

dydx=e(logx)log(logx)ddx{(logx)log(logx)}

=(logx)logx{ddx(logx).log(logx)+logxddxlog(logx)}

=(logx)logx{log(logx)x+logx×1logx×1x}

=(logx)logx{log(logx)x+1x}=(logx)logx{1+log(logx)x}

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