Question

Differentiate the following questions w.r.t. x.

log(log x), x>1.

Answer 1

Ley y = log(log x), x>1.

Differentiate both sides w.r.t. x,

$\frac{dy}{dx}=\frac{d}{dx}\left(log\right(logx\left)\right)=\frac{1}{logx}\left(\frac{d}{dx}\right(logx\left)\right)\Rightarrow \frac{dy}{dx}=\frac{1}{logx}.\frac{1}{x}=\frac{1}{xlogx}.x>1$