Question

Differentiate the following $w.r.t.x$.
$\sqrt{x}.cotx$

Answer 1

$\begin{array}{c}y=\sqrt{x}\cot x\\ \frac{dy}{dx}=\frac{1}{2\sqrt{x}}\cot x+\sqrt{x}\left(-\cos e{c}^{2}x\right)\\ =\frac{\cot x}{2\sqrt{x}}-\sqrt{x}\cos e{c}^{2}x.\end{array}$