Differentiate the following w.r.t. $x$ .
$(x^{2} + 3 x) (2 x + 7)$ .

6 x^{2} + 26 x + 20

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 x^{2} + 26 x + 21

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3 x^{2} + 26 x + 21

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6 x^{2} + 26 x + 21

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $6 x^{2} + 26 x + 21$
$\frac{d}{d x} (x^{2} + 3 x) (2 x + 7)$
$= \frac{d}{d x} {2 x^{3} + 7 x^{2} + 6 x^{2} + 21 x}$
$= \frac{d}{d x} {2 x^{3} + 13 x^{2} + 21 x}$
$= 6 x^{2} + 26 x + 21$

Suggest Corrections

Similar questions

$l i m x \to \infty {(\frac{3 x^{2} + 2 x + 1}{x^{2} + x + 2})}^{\frac{6 x + 1}{3 x + 2}} is equal to$

lim x \to \infty {(\frac{3 x^{2} + 2 x + 1}{x^{2} + x + 2})}^{\frac{6 x + 1}{3 x + 2}}

Solve for $x$ : $45 x - 20 - 26 x = 37$

3 x^{2} - 2 \sqrt{6} x + 2 = 0

12 x^{3} + 26 x - 17 x^{2} - 15

5 + 3 x^{2} - 2 x

Join BYJU'S Learning Program