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Question

Differentiate the function given below w.r.t. x:

(sinx+cosx)2


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Solution

Let y=(sinx+cosx)2

Differentiating with respect to x, we get

dydx=ddx(sinx+cosx)2

=2(cosx+sinx)ddx(cosx+sinx)

=2(cosx+sinx)(sinx+cosx)

=2(cos2xsin2x)

=2cos2x [cos2A=cos2Asin2A]


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