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Question

Differentiate the function with respect to x
2cot(x2)

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Solution

ddx[2cot(x2)]

=2.12cot(x2)×ddx[cot(x2)]
=sin(x2)cos(x2)×cosec2(x2)×ddx(x2)
=sin(x2)cos(x2)×1sin2(x2)×(2x)
=2xcosx2sinx2sinx2
=22x2sinx2cosx2sinx2
=22xsinx2sin(2x2)

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