Question

Differentiate the function with respect to $x$
$\cos \left(\sin x\right)$

Answer 1

Using chain rule,
$\frac{d}{dx}\left[\cos \right(\sin x\left)\right]=-\sin \left(\sin x\right).\frac{d}{dx}\left(\sin x\right)$

$=-\sin \left(\sin x\right).\cos x$

$=-\cos x\cdot \sin \left(\sin x\right)$