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Question

Differentiate the given function w.r.t. x:
(3x29x+5)9

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Solution

Let y=(3x29x+5)9
Using chain rule, we obtain
dydx=ddx(3x29x+5)9
=9(3x29x+5)8.ddx(3x29x+5)
=9(3x29x+5)8.(6x9)
=9(3x29x+5)8.3(2x3)
=27(3x29x+5)8(2x3)

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