Differentiate w . r . t $x$ : $sin 3 x cos 5 x$

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Solution

Let $y = sin 3 x . cos 5 x$

On differentiating w.r.t $x$ , we get
$\frac{d y}{d x} = cos 5 x \frac{d}{d x} (sin 3 x) + sin 3 x \frac{d}{d x} (cos 5 x)$
$\frac{d y}{d x} = 3 cos 3 x cos 5 x - 5 sin 3 x sin 5 x$

Hence, this is the answer.

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