wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Differentiate w.r.t x, the following function:
log1+cosx1cosx

Open in App
Solution

Let y=log1+cosx1cosx
On differentiating y with respect to x
dydx=ddxlog2cos2x/22sin2x/2
=ddxlogcotx/2
=1cotx/2ddxcotx/2
=sinx/2cosx/2(12×1sin2x/2)
=12sinx/2cosx/2=1sin2x/2
=1sinx=-cosec x

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Basic Theorems in Differentiation
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon