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Question

Differentiate w.r.t x, the following function:
log1+cosx1cosx

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Solution

Let y=log1+cosx1cosx
On differentiating y with respect to x
dydx=ddxlog2cos2x/22sin2x/2
=ddxlogcotx/2
=1cotx/2ddxcotx/2
=sinx/2cosx/2(12×1sin2x/2)
=12sinx/2cosx/2=1sin2x/2
=1sinx=-cosec x

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