Question

Differentiate with respect to $x$
$y=\sec \left(\tan \sqrt{x}\right)$

Answer 1

given that, $y=\sec \left(\tan \sqrt{x}\right)$

Using chain rule:

$y^{\prime }=\frac{dy}{dx}=\sec \left(\tan \sqrt{x}\right)\tan \left(\tan \sqrt{x}\right)\times {\sec }^2\sqrt{x}\times \frac{1}{\sqrt{x}}$