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Question

Differentiate (x25x+8)(x3+7x+9)in three ways mentioned below.

(a) By using product rule.

(b) By expanding the product to obtain a single polynomial.

(c) By logarithmic differentiation.

Do they all given the same answer?

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Solution

Ley y=(x25x+8)(x3+7x+9) .,........(i)

(a) Using product rule,

dydx=(x25x+8)ddx(x3+7x+9)+(x3+7x+9)ddx(x25x+8) =(x25x+8)(3x2+7)+(x3+7x+9)(2x5) =3x415x3+24x2+7x235x+56+2x4+14x2+18x5x335x45........(ii) =5x420x3+45x252x+11

(b) Writing y as a single polynomial,

y=(x25x+8)(x3+7x+9)=x55x4+15x326x2+11x+72Differentiating both sides w.r.t. x,we get dydx=ddx(x55x4+15x326x2+11x+72) =5x420x3+45x252x+11 ......(iii)

(c) Taking logarithms on both sides of Eq. (i), we get

log y=log{(x25x+8)(x3+7x+9)} log y=log{(x25x+8)+log(x3+7x+9)}Differentiating both sides w.r.t. x,we get1ydydx=1x25x+8ddx(x25x+8)+1x3+7x+9ddx(x3+7x+9) (Using chain rule)1ydydx=2x5x2+5x+8+3x2+7x3+7x+9 =(x25x+8)(x3+7x+9)(2x5x25x+8+3x2+7x3+7x+9)=(2x5)(x3+7x+9)+(3x2+7)(x25x+8)=2x4+14x2+18x5x335x45+3x415x3+24x2+7x235x+56=5x420x3+45x252x+11 .........(iv)

From Eqs. (ii), (iii) and (iv), we find that result is same in every case.


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