Question

Differentiate: $y=8\sin x\cos x$ w.r.t $x$

Answer 1

$y=8\sin x\cos x$

$y=4\times 2\sin x\cos x$

$y=4\times \sin 2x$

$y=4\sin 2x$

$\frac{dy}{dx}=4\frac{d}{dx}\left(\sin 2x\right)$

$=4\cos 2x\frac{d}{dx}\left(2x\right)$

$=8\cos 2x$