wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Differentiate y=sinx1cosx w.r.t x.

Open in App
Solution

According to question,

y=sinx1cosx×1+cosx1+cosx

y=sinx(1+cosx)1cos2x

y=sinx(1+cosx)sin2x

y=(1+cosx)sinx

y=cosecx+cotx

dydx=cosecx.cotxcosec2x

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Algebra of Derivatives
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon