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Question

Differentiate y=cosec xcotx w.r.t x

A
cosec x(cosec2x+cot2x)
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B
cosec x
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C
cosec x(cosec2x+cot2x)
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D
cosec x(cosec2xcot2x)
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Solution

The correct option is C cosec x(cosec2x+cot2x)
Given y=f(x)=cosec xcotx
By using multiplication rule derivative is given as
f(x)=cosec x(cotx)+(cosec x)cotx
=cosec x(cosec2x)+(cosec xcotx)cotx
=cosec x(cosec2x+cot2x)

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