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B
cosec x
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C
−cosec x(cosec2x+cot2x)
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D
cosec x(cosec2x−cot2x)
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Solution
The correct option is C−cosec x(cosec2x+cot2x) Given y=f(x)=cosec xcotx By using multiplication rule derivative is given as f′(x)=cosec x(cotx)′+(cosec x)′cotx =cosec x(−cosec2x)+(−cosec xcotx)cotx =−cosec x(cosec2x+cot2x)